$A$ proton and an electron are accelerated through the same potential difference. The ratio $\frac{\lambda_e}{\lambda_p}$ will be:

An electron of mass $m$ with an initial velocity $\overrightarrow{v}=v_0 \hat{i}$ $(v_0>0)$ enters an electric field $\overrightarrow{E}=-E_0 \hat{k}$. If the initial de Broglie wavelength is $\lambda_0$,the value after time $t$ would be $:-$

$A$ proton and an electron are accelerated by the same potential difference. Let $\lambda_e$ and $\lambda_p$ denote the de-Broglie wavelengths of the electron and the proton,respectively.

If an electron and a photon propagate in the form of waves having the same wavelength,it implies that they have the same

If the velocity of a free electron is doubled,the change in its de Broglie wavelength will be ...

Consider two particles of different masses. In which of the following situations will the heavier of the two particles have a smaller de-Broglie wavelength?